MMantap Math

SPM · Matematik 1449

Senarai rumus

Rumus yang boleh digunakan semasa menjawab Kertas 1 dan Kertas 2.

Nombor dan OperasiNumbers and Operations

Hukum indeksLaws of indices
aᵐ × aⁿ = aᵐ⁺ⁿaᵐ ÷ aⁿ = aᵐ⁻ⁿ(aᵐ)ⁿ = aᵐⁿ
Indeks negatif dan sifarNegative and zero indices
a⁻ⁿ = 1 ÷ aⁿa⁰ = 1
Indeks pecahanFractional indices
a¹ᐟⁿ = ⁿ√aaᵐᐟⁿ = (ⁿ√a)ᵐ = ⁿ√(aᵐ)
Faedah mudahSimple interest
I = Prt
Faedah kompaunCompound interest
MV = P(1 + r ÷ n)ⁿᵗ

Perkaitan dan AlgebraRelationship and Algebra

Jarak antara dua titikDistance between two points
√((x₂ − x₁)² + (y₂ − y₁)²)
Titik tengahMidpoint
(x, y) = ((x₁ + x₂) ÷ 2, (y₁ + y₂) ÷ 2)
KecerunanGradient
m = (y₂ − y₁) ÷ (x₂ − x₁)m = −(pintasan-y) ÷ (pintasan-x)m = −(y-intercept) ÷ (x-intercept)
Persamaan garis lurusEquation of a straight line
y = mx + c
Songsangan matriksInverse matrix
A = abcdA⁻¹ = 1 ÷ (ad − bc) × d−b−ca
Laju purataAverage speed
laju purata = jumlah jarak ÷ jumlah masaaverage speed = total distance ÷ total time
PecutanAcceleration
a = (v − u) ÷ t

Sukatan dan GeometriMeasurement and Geometry

Teorem PythagorasPythagoras' theorem
c² = a² + b²
Luas segi tigaArea of a triangle
½ × tapak × tinggi½ × base × height
Luas trapeziumArea of a trapezium
½ × hasil tambah sisi selari × tinggi½ × sum of parallel sides × height
BulatanCircle
lilitan = 2πjcircumference = 2πrluas = πj²area = πr²
Panjang lengkokArc length
(θ ÷ 360°) × 2πj(θ ÷ 360°) × 2πr
Luas sektorArea of a sector
(θ ÷ 360°) × πj²(θ ÷ 360°) × πr²
Isi padu prismaVolume of a prism
luas keratan rentas × panjangarea of cross section × length
Isi padu silinderVolume of a cylinder
πj²tπr²h
Isi padu konVolume of a cone
⅓πj²t⅓πr²h
Isi padu sferaVolume of a sphere
⁴⁄₃πj³⁴⁄₃πr³
Isi padu piramidVolume of a pyramid
⅓ × luas tapak × tinggi⅓ × base area × height
Luas permukaan silinderSurface area of a cylinder
2πj² + 2πjt2πr² + 2πrh
Luas permukaan konSurface area of a cone
πj² + πjsπr² + πrl
Luas permukaan sferaSurface area of a sphere
4πj²4πr²
Nisbah trigonometriTrigonometric ratios
sin θ = sisi bertentangan ÷ hipotenussin θ = opposite side ÷ hypotenusekos θ = sisi bersebelahan ÷ hipotenuscos θ = adjacent side ÷ hypotenusetan θ = sisi bertentangan ÷ sisi bersebelahantan θ = opposite side ÷ adjacent side
PembesaranEnlargement
k = PA′ ÷ PAluas imej = k² × luas objekarea of image = k² × area of object

Statistik dan KebarangkalianStatistics and Probability

MinMean
x̄ = Σx ÷ Nx̄ = Σfx ÷ Σf
VariansVariance
σ² = Σx² ÷ N − x̄²σ² = Σfx² ÷ Σf − x̄²
Sisihan piawaiStandard deviation
σ = √variansσ = √variance
KebarangkalianProbability
P(A) = n(A) ÷ n(S)P(A′) = 1 − P(A)
Peristiwa bergabungCombined events
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Peristiwa tak bersandarIndependent events
P(A ∩ B) = P(A) × P(B)